3[-2(j-8)]=4(4j+2)

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Solution for 3[-2(j-8)]=4(4j+2) equation:


Simplifying
3[-2(j + -8)] = 4(4j + 2)

Reorder the terms:
3[-2(-8 + j)] = 4(4j + 2)
3[(-8 * -2 + j * -2)] = 4(4j + 2)
3[(16 + -2j)] = 4(4j + 2)
[16 * 3 + -2j * 3] = 4(4j + 2)
[48 + -6j] = 4(4j + 2)

Reorder the terms:
48 + -6j = 4(2 + 4j)
48 + -6j = (2 * 4 + 4j * 4)
48 + -6j = (8 + 16j)

Solving
48 + -6j = 8 + 16j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-16j' to each side of the equation.
48 + -6j + -16j = 8 + 16j + -16j

Combine like terms: -6j + -16j = -22j
48 + -22j = 8 + 16j + -16j

Combine like terms: 16j + -16j = 0
48 + -22j = 8 + 0
48 + -22j = 8

Add '-48' to each side of the equation.
48 + -48 + -22j = 8 + -48

Combine like terms: 48 + -48 = 0
0 + -22j = 8 + -48
-22j = 8 + -48

Combine like terms: 8 + -48 = -40
-22j = -40

Divide each side by '-22'.
j = 1.818181818

Simplifying
j = 1.818181818

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